You can make use of differenceWith() with an isEqual() comparator, and invoke isEmpty to check if they are equal or not. var isArrayEqual = function(x, y) { return _(x).differenceWith(y, _.isEqual).isEmpty(); }; var result1 = isArrayEqual( [{a:1, b:2}, {c:3, d:4}], [{b:2, a:1}, {d:4, c:3}] ); var result2 = isArrayEqual( [{a:1, b:2, c: 1}, {c:3, d:4}], [{b:2, … Read more
In your first approach, no need for Lodash thanks to findIndex(): function upsert(array, element) { // (1) const i = array.findIndex(_element => _element.id === element.id); if (i > -1) array[i] = element; // (2) else array.push(element); } Example: const array = [ {id: 0, name: ‘Apple’, description: ‘fruit’}, {id: 1, name: ‘Banana’, description: ‘fruit’}, {id: … Read more
lodash allows nested object definitions: _.filter(summary.data, {category: {parent: ‘Food’}}); As of v3.7.0, lodash also allows specifying object keys in strings: _.filter(summary.data, [‘category.parent’, ‘Food’]); Example code in JSFiddle: https://jsfiddle.net/6qLze9ub/ lodash also supports nesting with arrays; if you want to filter on one of the array items (for example, if category is an array): _.filter(summary.data, {category: [{parent: … Read more
As Palpatim explained, the reason lies in the fact that _.debounce(…) returns a function, which when invoked does its magic. Therefore in your #anonFunction example, you have a key listener, which when invoked does nothing but return a function to the invoker, which does nothing with the return values from the event listener. This is … Read more
If you would use lodash instead of underscore, this would do: _.mapKeys(obj, (v, k) => _.camelCase(k)) This would convert both TitleCase and snake_case to camelCase. Note that it is not recursive though.
If you sort the outer array, you can use _.isEqual() since the inner array is already sorted. var array1 = [[‘a’, ‘b’], [‘b’, ‘c’]]; var array2 = [[‘b’, ‘c’], [‘a’, ‘b’]]; _.isEqual(array1.sort(), array2.sort()); //true Note that .sort() will mutate the arrays. If that’s a problem for you, make a copy first using (for example) .slice() … Read more
As lyyons pointed out in the comments, more idiomatic and lodashy way to do this would be to use _.remove, like this _.remove(obj.subTopics, { subTopicId: stToDelete }); Apart from that, you can pass a predicate function whose result will be used to determine if the current element has to be removed or not. _.remove(obj.subTopics, function(currentObject) … Read more
You can simply chain _.omit() with _.isUndefined and _.isNull compositions, and get the result with lazy evaluation. Demo var result = _(my_object).omit(_.isUndefined).omit(_.isNull).value(); Update March 14, 2016: As mentioned by dylants in the comment section, you should use the _.omitBy() function since it uses a predicate instead of a property. You should use this for lodash … Read more
Use _.groupBy and then _.map the resulting object to an array of objects. var newOutput = _(output) .groupBy(‘article’) .map(function(v, k){ return { article: k, titles: _.map(v, ‘title’) } }) .value(); var output = [{“article”:”BlahBlah”,”title”:”Another blah”},{“article”:”BlahBlah”,”title”:”Return of the blah”},{“article”:”BlahBlah2″,”title”:”The blah strikes back”},{“article”:”BlahBlah2″,”title”:”The blahfather”}]; let newOutput = _(output) .groupBy(‘article’) .map(function(v, k){ return { article: k, titles: _.map(v, … Read more
_.transform() the object to another object, and while passing the values to the new object, check if the value is an object and if it has the ‘reach’ property, and if so use _.omit() to get a new object without reach: var obj = { total: 350, SN1: { reach: 200, engagementRate: 1.35 }, SN2: … Read more