You can make use of differenceWith() with an isEqual() comparator, and invoke isEmpty to check if they are equal or not. var isArrayEqual = function(x, y) { return _(x).differenceWith(y, _.isEqual).isEmpty(); }; var result1 = isArrayEqual( [{a:1, b:2}, {c:3, d:4}], [{b:2, a:1}, {d:4, c:3}] ); var result2 = isArrayEqual( [{a:1, b:2, c: 1}, {c:3, d:4}], [{b:2, … Read more
You can use .map var data = [ {“key”:”fruit”,”value”:”apple”}, {“key”:”color”,”value”:”red”}, {“key”:”location”,”value”:”garden”} ]; var result = data.map(function (e) { var element = {}; element[e.key] = e.value; return element; }); console.log(result); also if you use ES2015 you can do it like this var result = data.map((e) => { return {[e.key]: e.value}; }); Example
Because name is a non-standard, non-writable property of function objects. Function declarations and named function expressions are named, while you have an anonymous function expression whose name is “”. You probably wanted a plain object: var person = { name: “John Smith”, age: 21, profession: “Web Developer” };
A simple self-calling function can do it. function removeMeta(obj) { for(prop in obj) { if (prop === ‘$meta’) delete obj[prop]; else if (typeof obj[prop] === ‘object’) removeMeta(obj[prop]); } } var myObj = { “part_one”: { “name”: “My Name”, “something”: “123”, “$meta”: { “test”: “test123” } }, “part_two”: [ { “name”: “name”, “dob”: “dob”, “$meta”: { … Read more
This is easily done with the Array.prototype.map() function: var keyArray = objArray.map(function(item) { return item[“key”]; }); If you are going to do this often, you could write a function that abstracts away the map: function pluck(array, key) { return array.map(function(item) { return item[key]; }); } In fact, the Underscore library has a built-in function called … Read more
You can use array.filter, this takes a function that is passed each item of the array and returns true or false and returns a new array that only has items where the function passed to filter will return true. You can partially apply a curried function. Example of curried function: const plus = a => … Read more
One way to do it is through object destructuring and an arrow function: let source = { x: 120, y: 200, z: 150, radius: 10, color: ‘red’, }; let result = (({ x, y, z }) => ({ x, y, z }))(source); console.log(result); The way this works is that the arrow function (({ x, y, … Read more
No, there is no way to access the object literal that is currently being defined from within the definition itself. If you want to set properties based on the values of other properties, then you either need to base them both on some external value (that is not a property itself) or run an initializer … Read more
Unless the variable k is defined, that’s probably what’s causing your trouble. Something like this will do what you want: var new_tweets = { }; new_tweets.k = { }; new_tweets.k.tweet_id = 98745521; new_tweets.k.user_id = 54875; new_tweets.k.data = { }; new_tweets.k.data.in_reply_to_screen_name=”other_user”; new_tweets.k.data.text=”tweet text”; // Will create the JSON string you’re looking for. var json = JSON.stringify(new_tweets); … Read more
Your question seems to be about why we can’t access array and array-like elements using the dot notation like this: const v = a.0; It’s described in the ECMAScript specification: The dot notation is explained by the following syntactic conversion: MemberExpression . IdentifierName And identifiers may not start with a digit as described here: IdentifierName … Read more