An elaborated type specifier is a type name preceded by either the class, struct, enum, or union keyword. class identifier struct identifier enum identifier union identifier An elaborated type specifier is used either for emphasis, or to reveal a type name that is hidden by the declaration of a variable with the same name in … Read more
The answer is in the javadoc : The char data type (and therefore the value that a Character object encapsulates) are based on the original Unicode specification, which defined characters as fixed-width 16-bit entities. The Unicode standard has since been changed to allow for characters whose representation requires more than 16 bits. The range of … Read more
are you required to use the & modifier to pass-by-reference? Technically/semantically, the answer is yes, even with objects. This is because there are two ways to pass/assign an object: by reference or by identifier. When a function declaration contains an &, as in: function func(&$obj) {} The argument will be passed by reference, no matter … Read more
Try this instead, remove the SelectCommand property and SelectParameters: <asp:SqlDataSource ID=”SqlDataSource1″ runat=”server” ConnectionString=”<%$ ConnectionStrings:itematConnectionString %>”> Then in the code behind do this: SqlDataSource1.SelectParameters.Add(“userId”, userId.ToString()); SqlDataSource1.SelectCommand = “SELECT items.name, items.id FROM items INNER JOIN users_items ON items.id = users_items.id WHERE (users_items.user_id = @userId) ORDER BY users_items.date DESC” While this worked for me, the following code also … Read more
It’s declared inside a closure, which means it can only be accessed there. If you want a variable accessible globally, you can remove the var: $(function(){ value = “10”; }); value; // “10” This is equivalent to writing window.value = “10”;.
Only x is a pointer to int; y and z are regular ints. This is one aspect of C declaration syntax that trips some people up. C uses the concept of a declarator, which introduces the name of the thing being declared along with additional type information not provided by the type specifier. In the … Read more
Technically the global keyword is used inside a function, not outside. But you shouldn’t really use this approach. See Why global variables are evil. Instead, pass a variable as a parameter: function($param) { $param += 1; return $param; } $var = 1; $var = function($var); // get your value of 2
You could try something like this: #define DUMP(varname) fprintf(stderr, “%s = %x”, #varname, varname); I used to use this header I wrote, when I was new to C, it might contain some useful ideas. For example this would allow you to print a C value and provide the format specifier in one (as well as … Read more
You don’t. This is a language feature to prevent the standard unwanted side-effect of assignment returning a value, as described in the Swift book: Unlike the assignment operator in C and Objective-C, the assignment operator in Swift does not itself return a value. The following statement is not valid: if x = y { // … Read more