C variable declarations after function heading in definition [duplicate]
That looks like K&R (pre-ANSI) style. I don’t think it’s valid C99, but are they using C99? Joel
variables
c++ warning: address of local variable
c++ warning: address of local variable
Why can’t I do polymorphism with normal variables?
The answer is copy semantics. When you pass an object by value in C++, e.g. printArea(Shape shape) a copy is made of the object you pass. And if you pass a derived class to this function, all that’s copied is the base class Shape. If you think about it, there’s no way the compiler could … Read more
Polymorphism with instance variables [duplicate]
There is no polymorphism for fields in Java. There is however, inheritance. What you’ve effectively done is create two fields in your Rectangle class, with the same name. The names of the field are, effectively: public class Rectangle { public int Shape.x; public int Rectangle.x; } The above doesn’t represent valid Java, its just an … Read more
Dynamic Variable Naming and Reference (ColdFusion)
One Option: Setting a dynamic variable name: <cfset variables[“GC” & AID] = “Testing” /> Output the value of the dynamic variable name: <cfoutput>#variables[“GC” & AID]#</cfoutput> Another Option: Setting a dynamic variable name: <cfset variables[“GC#AID#”] = “Testing” /> Output the value of the dynamic variable name: <cfoutput>#variables[“GC#AID#”]#</cfoutput>
Comparing IEEE floats and doubles for equality
The best approach I think is to compare ULPs. bool is_nan(float f) { return (*reinterpret_cast<unsigned __int32*>(&f) & 0x7f800000) == 0x7f800000 && (*reinterpret_cast<unsigned __int32*>(&f) & 0x007fffff) != 0; } bool is_finite(float f) { return (*reinterpret_cast<unsigned __int32*>(&f) & 0x7f800000) != 0x7f800000; } // if this symbol is defined, NaNs are never equal to anything (as is normal … Read more
Why are symbols in Ruby not thought of as a type of variable?
Symbols are not variables, but a type of literal value, like numerals and quoted strings. Significantly, symbols are used to represent variables and other named values in the Ruby runtime. So when the Ruby interpreter sees the name foo used as a variable or method name, what it looks up in the Hash of runtime … Read more
original variable name passed to function? [duplicate]
It’s not possible. Even pass-by-reference won’t help you. You’ll have to pass the name as a second argument. But what you have asked is most assuredly not a good solution to your problem.
How to increment variable names/Is this a bad idea [duplicate]
You should append all the values to a list, that allows you to easily iterate through the values later as well as not littering your namespace with useless variables and magic.
Java String variable setting – reference or value?
java Strings are immutable, so your reassignment actually causes your variable to point to a new instance of String rather than changing the value of the String. String s1 = “ab”; String s2 = s1; s1 = s1 + “c”; System.out.println(s1 + ” ” + s2); on line 2, s1 == s2 AND s1.equals(s2). After … Read more