You can give an explicit template argument: bar<int(int)>(3, foo); or cast the ambiguous function name to a type from which the template argument can be deduced: bar(3, static_cast<int(*)(int)>(foo)); or wrap it in another function (or function object) to remove the ambiguity bar(3, [](int x){return foo(x);});
The unspecialized function templates are also called the underlying base templates. Base templates can be specialized. The overloading rules to see which ones get called in different situations, are pretty simple, at least at a high level: Nontemplate functions are first-class citizens. A plain old nontemplate function that matches the parameter types as well as … Read more
So to start with, the first expression can only possibly call the first overload. It is not a valid expression for a Func<Task> because there is a code path that returns an invalid value (void instead of Task). () => while(true) is actually a valid method for either signature. (It, along with implementations such as … Read more
Overloading a method (or function) in C++ is the ability for functions of the same name to be defined as long as these methods have different signatures (different set of parameters). Method overriding is the ability of the inherited class rewriting the virtual method of the base class. a) In overloading, there is a relationship … Read more
The general rule that applies here is this: if one method signature is strictly more specific than the other, then Java chooses it without an error. Intuituively, a method signature is more specific if you could delete it entirely and the other, less specific one would be applicable to each existing invocation. When presented with … Read more
You have to specify which method you want: class SomeType { void Foo(int size, string bar) { } void Foo() { } } SomeType obj = new SomeType(); // call with int and string arguments obj.GetType() .GetMethod(“Foo”, new Type[] { typeof(int), typeof(string) }) .Invoke(obj, new object[] { 42, “Hello” }); // call without arguments obj.GetType() … Read more
Method overloading means making multiple versions of a function based on the inputs. For example: public Double doSomething(Double x) { … } public Object doSomething(Object y) { … } The choice of which method to call is made at compile time. For example: Double obj1 = new Double(); doSomething(obj1); // calls the Double version Object … Read more
If the system is changing so often that using an indexed array is the best solution, I’d say this is the least of your worries. 🙂 In general functions/methods shouldn’t take too many arguments (5 plus or minus 2 being the maximum) and I’d say that you should stick to using named (and ideally type … Read more
Section 12.5 from Templates the Complete Guide (Amazon) contains this quote: You may legitimately wonder why only class templates can be partially specialized. The reasons are mostly historical. It is probably possible to define the same mechanism for function templates (see Chapter 13). In some ways the effect of overloading function templates is similar, but … Read more
Nothing will happen- meaning you won’t get an error or a warning as passing the parameters in javascript is optional. All the parameters that weren’t “supplied” will have the undefined value. function foo(x, y, z){ //… } foo(1); Inside the foo function now: function foo(x, y, z){ x === 1 y === undefined z === … Read more