list extend() to index, inserting list elements not only to the end

Sure, you can use slice indexing: a_list[1:1] = b_list Just to demonstrate the general algorithm, if you were to implement the my_extend function in a hypothetical custom list class, it would look like this: def my_extend(self, other_list, index): self[index:index] = other_list But don’t actually make that a function, just use the slice notation when you … Read more

How to subclass Python list without type problems?

Firstly, I recommend you follow Björn Pollex’s advice (+1). To get past this particular problem (type(l2 + l3) == CustomList), you need to implement a custom __add__(): def __add__(self, rhs): return CustomList(list.__add__(self, rhs)) And for extended slicing: def __getitem__(self, item): result = list.__getitem__(self, item) try: return CustomList(result) except TypeError: return result I also recommend… pydoc … Read more

Column of lists, convert list to string as a new column

List Comprehension If performance is important, I strongly recommend this solution and I can explain why. df[‘liststring’] = [‘,’.join(map(str, l)) for l in df[‘lists’]] df lists liststring 0 [1, 2, 12, 6, ABC] 1,2,12,6,ABC 1 [1000, 4, z, a] 1000,4,z,a You can extend this to more complicated use cases using a function. def try_join(l): try: … Read more

My async call is returning before list is populated in forEach loop

This code Future<List<String>> readHeaderData() async { List<String> l = new List(); List<String> files = await readHeaders(); // Gets filenames files.forEach((filename) async { final file = await File(filename); String contents = await file.readAsString(); User user = User.fromJson(json.decode(contents)); String name = user.NameLast + “, ” + user.NameFirst; print(name); l.add(name); } return l; } returns the list l … Read more

Comparing 2 lists consisting of dictionaries with unique keys in python

Assuming that the dicts line up like in your example input, you can use the zip() function to get a list of associated pairs of dicts, then you can use any() to check if there is a difference: >>> list_1 = [{‘unique_id’:’001′, ‘key1′:’AAA’, ‘key2′:’BBB’, ‘key3′:’EEE’}, {‘unique_id’:’002′, ‘key1′:’AAA’, ‘key2′:’CCC’, ‘key3′:’FFF’}] >>> list_2 = [{‘unique_id’:’001′, ‘key1′:’AAA’, ‘key2′:’DDD’, … Read more

Hata!: SQLSTATE[HY000] [1045] Access denied for user 'divattrend_liink'@'localhost' (using password: YES)