If your intention is to some other scope, iterate over it, do some other stuff, then be able to iterate over it again later on in that same scope. Then the only thing you shouldn’t try doing is passing the iterator, instead pass the generator: var generator = function*() { yield 1; yield 2; yield … Read more
Try: var g = f(); // this question is over this value. g.next(); // returns: { value: 1, done: false } g.next(123); // returns: { value: 2, done: false } g.next(456); // returns: { value: [123, 456], done: true }
Is there a means to define equality for my objects to solve my problem? No not really. There has been some discussion about this on the mailing list. The result is: Build your own Set/Map abstraction on top of Set/Map, which would convert the objects to a primitive value according to your hashing function. Wait … Read more
What I don’t understand is how this relates to destructuring. Within removeBreakpoint, you can use url, line, and column directly. The destructuring happens when removeBreakpoint is called with an options object; that object’s matching properties are destructured into individual arguments. Is the idea that you permit the ability to pass an object into this function … Read more
if no such option exists, then maybe there is a nice idiomatic one-liner for doing that ? like, using for…of, or similar ? Indeed, there are several ways to convert a Set to an Array: Using Array.from: Note: safer for TypeScript. const array = Array.from(mySet); Simply spreading the Set out in an array: Note: Spreading … Read more
From the Arrow functions examples, (() => “foobar”)() // returns “foobar” So, the function invocation operator should be outside. (() => { //… })(); Sample: http://www.es6fiddle.net/hsb8s1sj/
Believe it or not… Testing for presence of “=>” in string representation of a function is likely the most reliable way (but not 100%). Obviously we can’t test against either of 2 conditions you mentioned — lack of prototype property and lack of [[Construct]] as that might give false positives with either host objects or … Read more
Using the ES2015 Spread operator: […Array(n)].map() const res = […Array(10)].map((_, i) => { return i * 10; }); // as a one liner const res = […Array(10)].map((_, i) => i * 10); Or if you don’t need the result: […Array(10)].forEach((_, i) => { console.log(i); }); // as a one liner […Array(10)].forEach((_, i) => console.log(i)); Or … Read more
If you use Babel you can use the following syntax to copy property b from x into variable b and then copy rest of properties into variable y: let x = {a: 1, b: 2, c: 3, z:26}; let {b, …y} = x; and it will be transpiled into: “use strict”; function _objectWithoutProperties(obj, keys) { … Read more
No. The bind operator (spec proposal) comes in two flavours: Method extraction ::obj.method ≡ obj.method.bind(obj) “virtual method” calls obj::function ≡ function.bind(obj) obj::function(…) ≡ function.call(obj, …) Neither of them feature partial application. For what you want, you should use an arrow function: (…args) => this.handleStuff(‘stuff’, …args) ≡ this.handleStuff.bind(this, ‘stuff’)