It would be this
array=($(ls -d */))
EDIT: See Gordon Davisson’s solution for a more general answer (i.e. if your filenames contain special characters). This answer is merely a syntax correction.
It would be this
array=($(ls -d */))
EDIT: See Gordon Davisson’s solution for a more general answer (i.e. if your filenames contain special characters). This answer is merely a syntax correction.