It’s being parsed as this:
long i = (byte)( +(char)( -(int)( +(long)(-1) ) ) );
where all the +
and -
operators are unary +
or -
.
In which case, the 1
gets negated twice, so it prints out as a 1
.
It’s being parsed as this:
long i = (byte)( +(char)( -(int)( +(long)(-1) ) ) );
where all the +
and -
operators are unary +
or -
.
In which case, the 1
gets negated twice, so it prints out as a 1
.