My guess is that you have a problem since you don’t close your select-tag after the loop. Consider separating your database-related code from the markup, it will help you to spot such mistakes easily <?php … // SQL part $sql = mysqli_query($connection, “SELECT username FROM users”); $data = $sql->fetch_all(MYSQLI_ASSOC); // HTML part ?> <tr> <td>Owner</td> … Read more
The correct options are (in increasing order of recommendation): # Single POSIX test command with -o operator (not recommended anymore). # Quotes strongly recommended to guard against empty or undefined variables. while [ “$stats” -gt 300 -o “$stats” -eq 0 ] # Two POSIX test commands joined in a list with ||. # Quotes strongly … Read more
A While/Wend loop can only be exited prematurely with a GOTO or by exiting from an outer block (Exit sub/function or another exitable loop) Change to a Do loop instead: Do While True count = count + 1 If count = 10 Then Exit Do End If Loop Or for looping a set number of … Read more
while true; do foo; sleep 2; done By the way, if you type it as a multiline (as you are showing) at the command prompt and then call the history with arrow up, you will get it on a single line, correctly punctuated. $ while true > do > echo “hello” > sleep 2 > … Read more
It’s like this: def printTTriangle(height): row = 1 while row < height+1: col = 1 while col < row+1: print ‘T’, col += 1 print row += 1 Here’s how I did it. For example, let’s convert this line: for row in range(1, height+1): First step: create an iteration variable and initialize it in the … Read more
The hasNextInt call blocks until it has enough information to make the decision of “yes/no”. Press Ctrl+Z on Windows (or Ctrl+D on “unix”) to close the standard input stream and trigger an EOF. Alternatively, type in a non-integer and press enter. Console input is normally line-buffered: enter must be pressed (or EOF triggered) and the … Read more
The problem is that nextLine() “Advances this scanner past the current line”. So when you call nextLine() in the while condition, and don’t save the return value, you’ve lost that line of the user’s input. The call to nextLine() on line 3 returns a different line. You can try something like this Scanner scanner=new Scanner(System.in); … Read more
You can use non-blocking read from stdin: import sys import os import fcntl import time fl = fcntl.fcntl(sys.stdin.fileno(), fcntl.F_GETFL) fcntl.fcntl(sys.stdin.fileno(), fcntl.F_SETFL, fl | os.O_NONBLOCK) while True: print(“Waiting for user input”) try: stdin = sys.stdin.read() if “\n” in stdin or “\r” in stdin: break except IOError: pass time.sleep(1)
You get the ValueError because your code probably has for line in original: in addition to original.readline(). An easy solution which fixes the problem without making your program slower or consume more memory is changing for line in original: … to while True: line = original.readline() if not line: break …
set /a countfiles-=%countfiles% This will set countfiles to 0. I think you want to decrease it by 1, so use this instead: set /a countfiles-=1 I’m not sure if the for loop will work, better try something like this: :loop cscript /nologo c:\deletefile.vbs %BACKUPDIR% set /a countfiles-=1 if %countfiles% GTR 21 goto loop