sorted(iterable): Return a new sorted list from the items in iterable. CODE import pandas as pd df = pd.DataFrame({‘A’:[1,1,3,2,6,2,8]}) a = df[‘A’].unique() print(sorted(a)) OUTPUT [1, 2, 3, 6, 8]
array = [[‘a’,’b’], [‘a’, ‘b’,’c’], [‘a’]] result = {x for l in array for x in l}
A variation on Neil’s solution which doesn’t need an extension is: create table friendz ( from_id int, to_id int ); create unique index ifriendz on friendz(greatest(from_id,to_id), least(from_id,to_id)); Neil’s solution lets you use an arbitrary number of columns though. We’re both relying on using expressions to build the index which is documented https://www.postgresql.org/docs/current/indexes-expressional.html
A very simple answer if you say you don’t care which address is used. SELECT CName, MIN(AddressLine) FROM MyTable GROUP BY CName If you want the first according to, say, an “inserted” column then it’s a different query SELECT M.CName, M.AddressLine, FROM ( SELECT CName, MIN(Inserted) AS First FROM MyTable GROUP BY CName ) foo … Read more
The name attribute is only valid on the <form> and form elements (<input>,<textarea> and <select>). It’s used to specify the name to associate with the name/value pair that is submitted on a form post. For example: <input type=”checkbox” name=”foo” value=”1″ /> if checked will submit foo=1. In the DOM you can reference form elements from … Read more
Just use: $output = array_merge($array1, $array2); That should solve it. Because you use string keys if one key occurs more than one time (like ’44’ in your example) one key will overwrite preceding ones with the same name. Because in your case they both have the same value anyway it doesn’t matter and it will … Read more
There are actually many ways you can detect a “unique” user. Many of these methods are used by our marketing friends. It get’s even easier when you have plugins enabled such as Java, Flash etc. Currently my favorite presentation of cookie based tracking is evercookie (http://samy.pl/evercookie/). It creates a “permanent” cookie via multiple storage mechanisms, … Read more
I think you would do it like this: I would use two iterators on the vector : The first of one reads the data and inserts it a temporary set. When the read data was not in the set you copy it from the first iterator to the second and increment it. At the end … Read more
Unless you acquire a lock on a whole table, it is basically not possible to check for unicity using a SQL query (any concurrent transaction could modify data after a manual check but before the commit of the ongoing transaction). In other words, it isn’t possible to implement a valid unique verification at the Java … Read more