There are much better ways to sort. You need a comparison function that returns the right values: -1, 0, and 1. localeCompare() is such a comparison function. You can just move the DOM elements around rather than regenerating the HTML. You can get the LI elements directly in the original selector. “#table1” is a more … Read more
From “The Darkside” in his article Parallel Extensions to the .Net Framework we have this parallel extensions version of quicksort: (Edit: Since the link is now dead, interested readers may find an archive of it at the Wayback Machine) private void QuicksortSequential<T>(T[] arr, int left, int right) where T : IComparable<T> { if (right > … Read more
I would make it an array and use the sort function: $string = ‘bac’; $stringParts = str_split($string); sort($stringParts); echo implode($stringParts); // abc
Update 2: As we can see in Sort.swift, sort() now uses a “modified timsort” in Swift 5. Timsort is a … hybrid stable sorting algorithm, derived from merge sort and insertion sort … In the worst case, Timsort takes O(n log n) comparisons to sort an array of n elements. In the best case, which … Read more
To directly answer your question: Your sorting algorithm is technically not O(n) but rather O(n + max), since you need to create an array of size max, which takes O(max) time. This isn’t a problem; in fact, it’s a special case of a well-known sorting algorithm that breaks the Ω(n log n) barrier. So what … Read more
Function objects do not define their own comparisons or rich comparisons. Instead, they inherit from type objects which implement rich comparisons based on the object’s address in memory. So yes, it effectively uses addresses just like the built-in id() function does. In Python 3, functions are no longer orderable.
The following code works perfectly public Comparator<Map<String, String>> mapComparator = new Comparator<Map<String, String>>() { public int compare(Map<String, String> m1, Map<String, String> m2) { return m1.get(“name”).compareTo(m2.get(“name”)); } } Collections.sort(list, mapComparator); But your maps should probably be instances of a specific class.
The time could be reduced to linear time: Use the selection algorithm, which effectively find the k-th element in a un-sorted array in linear time. You can either use a variant of quick sort or more robust algorithms. Get the top k using the pivot got in step 1.
In C, you can use the built in qsort command: int compare( const void* a, const void* b) { int int_a = * ( (int*) a ); int int_b = * ( (int*) b ); if ( int_a == int_b ) return 0; else if ( int_a < int_b ) return -1; else return 1; … Read more
The Spread syntax introduced with ECMAScript6 (e.g., […object]) makes this relatively straightforward using an Array’s reduce method: const arr = [ { flag: true, other: 1 }, { flag: true, other: 2 }, { flag: false, other: 3 }, { flag: true, other: 4 }, { flag: true, other: 5 }, { flag: true, other: … Read more