You need not to use std::sort. It can be done in a simpler way: if ( std::adjacent_find( myvector.begin(), myvector.end(), std::not_equal_to<>() ) == myvector.end() ) { std::cout << “All elements are equal each other” << std::endl; }
A better approach would be: new Date().valueOf(); instead of new Date().getUTCMilliseconds(); valueOf() is “most likely” a unique number. http://www.w3schools.com/jsref/jsref_valueof_date.asp.
Use Array#uniq with a block: @photos = @photos.uniq { |p| p.album_id }
I think this would work: var result = myClassObject.GroupBy(x => x.BillId) .Where(x => x.Count() == 1) .Select(x => x.First()); Fiddle here
The problem is that your Element class has not overridden the equals and hashCode methods or these implementations are broken. From Object#equals method javadoc: The equals method implements an equivalence relation on non-null object references: It is reflexive: for any non-null reference value x, x.equals(x) should return true. It is symmetric: for any non-null reference … Read more
For C/C++: #include <IOKit/IOKitLib.h> void get_platform_uuid(char * buf, int bufSize) { io_registry_entry_t ioRegistryRoot = IORegistryEntryFromPath(kIOMasterPortDefault, “IOService:/”); CFStringRef uuidCf = (CFStringRef) IORegistryEntryCreateCFProperty(ioRegistryRoot, CFSTR(kIOPlatformUUIDKey), kCFAllocatorDefault, 0); IOObjectRelease(ioRegistryRoot); CFStringGetCString(uuidCf, buf, bufSize, kCFStringEncodingMacRoman); CFRelease(uuidCf); }
If you need to allow NULL values, use a UNIQUE constraint (or index) instead of a PRIMARY KEY (and add a surrogate PK column – I suggest a serial or IDENTITY column in Postgres 10 or later). Auto increment table column A UNIQUE constraint allows columns to be NULL: CREATE TABLE distributor ( distributor_id GENERATED … Read more
You can get this functionality in numpy by comparing each element with it’s neighbor; v[:-1] != v[1:] array([False, False, False, False, True, False, False, True, True, True, True, True, True, True, True, True, False, False], dtype=bool) to get the indices you use the “where” function np.where(v[:-1] != v[1:])[0] array([ 4, 7, 8, 9, 10, 11, … Read more
This is actually very simple. It is much easier to find unique values, if the values are sorted first: function sort_unique(arr) { if (arr.length === 0) return arr; arr = arr.sort(function (a, b) { return a*1 – b*1; }); var ret = [arr[0]]; for (var i = 1; i < arr.length; i++) { //Start loop … Read more