I suggest to replace sed “s/regex/replace/” file with sed “s|regex|replace|” file if your sed supports it. Then it is no longer necessary to escape the slashes. The character directly after the s determines which character is the separator, which must appear three times in the s command.
A bit late to the party but for the benefit of others, I found the ‘w’ flag to be exactly what I was looking for. sed -i “s/$pattern/$new_pattern/w changelog.txt” “$filename” if [ -s changelog.txt ]; then # CHANGES MADE, DO SOME STUFF HERE else # NO CHANGES MADE, DO SOME OTHER STUFF HERE fi changelog.txt … Read more
Escape the .: sed ‘s/foo\./foo_/g’ file.php Example: ~$ cat test.txt foo.bar ~$ sed ‘s/foo\./foo_/g’ test.txt foo_bar
sed -n ‘/matched/,$p’ file awk ‘/matched/,0’ file
You can either use: “texta’textb” (APOSTROPHE inside QUOTATION MARKs) or ‘texta’\”textb’ (APOSTROPHE text APOSTROPHE, then REVERSE SOLIDUS, APOSTROPHE, then APOSTROPHE more text APOSTROPHE) I used unicode character names. REVERSE SOLIDUS is more commonly known as backslash. In the latter case, you close your apostrophe, then shell-quote your apostrophe with a backslash, then open another apostrophe … Read more
The call command has this functionality built in. To quote the help for call: Substitution of batch parameters (%n) has been enhanced. You can now use the following optional syntax: %~1 – expands %1 removing any surrounding quotes (“) Here is a primitive example: @echo off setlocal set mystring=”this is some quoted text” echo mystring=%mystring% … Read more
Here is one method: $ awk ‘{s+=$1}END{print “ave:”,s/NR}’ RS=” ” file ave: 54.646
Try: Ctrl+V and then press Tab.
You can do this by swapping values of the first two fields: awk ‘ { t = $1; $1 = $2; $2 = t; print; } ‘ input_file
If you wanted to remove a certain NUMBER of path components, you should use cut with -d”https://stackoverflow.com/”. For example, if path=/home/dude/some/deepish/dir: To remove the first two components: # (Add 2 to the number of components to remove to get the value to pass to -f) echo $path | cut -d”https://stackoverflow.com/” -f4- # output: # some/deepish/dir … Read more