You want to run 22,000 linear regressions and extract the coefficients? That’s simple to do from a coding standpoint. set.seed(1) # number of columns in the Lung and Blood data.frames. 22,000 for you? n <- 5 # dummy data obs <- 50 # observations Lung <- data.frame(matrix(rnorm(obs*n), ncol=n)) Blood <- data.frame(matrix(rnorm(obs*n), ncol=n)) Age <- sample(20:80, … Read more
This will do: function hasRepeats (str) { return /(.).*\1/.test(str); }
Use np.repeat: Version 1: Try using np.repeat: newdf = pd.DataFrame(np.repeat(df.values, 3, axis=0)) newdf.columns = df.columns print(newdf) The above code will output: Person ID ZipCode Gender 0 12345 882 38182 Female 1 12345 882 38182 Female 2 12345 882 38182 Female 3 32917 271 88172 Male 4 32917 271 88172 Male 5 32917 271 88172 Male … Read more
Use each argument: rep(c(1027, 1028, 1030, 1032, 1037), each = 6) # [1] 1027 1027 1027 1027 1027 1027 # [7] 1028 1028 1028 1028 1028 1028 # [13] 1030 1030 1030 1030 1030 1030 # [19] 1032 1032 1032 1032 1032 1032 # [25] 1037 1037 1037 1037 1037 1037 times argument: rep(c(1027, 1028, … Read more
Jason Scheirer’s answer is correct but could use some more exposition. First off, to repeat a string an integer number of times, you can use overloaded multiplication: >>> ‘abc’ * 7 ‘abcabcabcabcabcabcabc’ So, to repeat a string until it’s at least as long as the length you want, you calculate the appropriate number of repeats … Read more
There are a number of ways you could achieve this. Solution A: If the range of numbers isn’t large (let’s say less than 10), you could just keep track of the numbers you’ve already generated. Then if you generate a duplicate, discard it and generate another number. Solution B: Pre-generate the random numbers, store them … Read more
In [1]: data = np.arange(-50,50,10) To repeat each element 5 times use np.repeat: In [3]: np.repeat(data, 5) Out[3]: array([-50, -50, -50, -50, -50, -40, -40, -40, -40, -40, -30, -30, -30, -30, -30, -20, -20, -20, -20, -20, -10, -10, -10, -10, -10, 0, 0, 0, 0, 0, 10, 10, 10, 10, 10, 20, 20, … Read more
reindex+ repeat df.reindex(df.index.repeat(df.persons)) Out[951]: code . role ..1 persons 0 123 . Janitor . 3 0 123 . Janitor . 3 0 123 . Janitor . 3 1 123 . Analyst . 2 1 123 . Analyst . 2 2 321 . Vallet . 2 2 321 . Vallet . 2 3 321 . Auditor … Read more
var helloWorldTimer = NSTimer.scheduledTimerWithTimeInterval(60.0, target: self, selector: Selector(“sayHello”), userInfo: nil, repeats: true) func sayHello() { NSLog(“hello World”) } Remember to import Foundation. Swift 4: var helloWorldTimer = Timer.scheduledTimer(timeInterval: 60.0, target: self, selector: #selector(ViewController.sayHello), userInfo: nil, repeats: true) @objc func sayHello() { NSLog(“hello World”) }
You missed the each= argument to rep(): R> n <- 3 R> rep(1:5, each=n) [1] 1 1 1 2 2 2 3 3 3 4 4 4 5 5 5 R> so your example can be done with a simple R> rep(1:8, each=20)