This traverse generator function can be used to iterate over all the values: def traverse(o, tree_types=(list, tuple)): if isinstance(o, tree_types): for value in o: for subvalue in traverse(value, tree_types): yield subvalue else: yield o data = [(1,1,(1,1,(1,”1″))),(1,1,1),(1,),1,(1,(1,(“1”,)))] print list(traverse(data)) # prints [1, 1, 1, 1, 1, ‘1’, 1, 1, 1, 1, 1, 1, 1, ‘1’] … Read more
It depends on which version of IPython you have. If you have 1.x: from IPython import get_ipython ipython = get_ipython() If you have an older version: import IPython.core.ipapi ipython = IPython.core.ipapi.get() or import IPython.ipapi ipython = IPython.ipapi.get() Once that’s done, run a magic command like this: ipython.magic(“timeit abs(-42)”) Note: The script must be run via … Read more
Call the pd.DataFrame constructor directly: df = pd.DataFrame(table, columns=headers) df Heading1 Heading2 0 1 2 1 3 4
Calls to itertools.imap() in Python 2 or map() in Python 3 can be replaced by equivalent generator expressions: sum(1 for dummy in it) This also uses a lazy generator, so it avoids materializing a full list of all iterator elements in memory.
The error code 10060 means it cannot connect to the remote peer. It might be because of the network problem or mostly your setting issues, such as proxy setting. You could try to connect the same host with other tools(such as ncat) and/or with another PC within your same local network to find out where … Read more
You can use np.sign in combination with np.diff and np.argwhere to obtain the indices of points where the lines cross (in this case, the points are [ 0, 149, 331, 448, 664, 743]): import numpy as np import matplotlib.pyplot as plt x = np.arange(0, 1000) f = np.arange(0, 1000) g = np.sin(np.arange(0, 10, 0.01) * … Read more
Since you’ve tagged this question with sympy, I will give such an example. From the documentation: http://docs.sympy.org/latest/modules/plotting.html. from sympy import var, plot_implicit var(‘x y’) plot_implicit(x*y**3 – y*x**3)
There is an automatic margin set at the edges, which ensures the data to be nicely fitting within the axis spines. In this case such a margin is probably desired on the y axis. By default it is set to 0.05 in units of axis span. To set the margin to 0 on the x … Read more
Decode the bytes object to produce a string: >>> b”abcde”.decode(“utf-8”) ‘abcde’ The above example assumes that the bytes object is in UTF-8, because it is a common encoding. However, you should use the encoding your data is actually in!
First, what happens when T0 is not None? I would test that, then I would adjust the values I pass to plt.subplot(); maybe try values 131, 132, and 133, or values that depend whether or not T0 exists. Second, after plt.show() is called, a new figure is created. To deal with this, you can Call … Read more