I typically don’t use or find a need for class-level loggers, but I keep my modules at a few classes at most. A simple: import logging LOG = logging.getLogger(__name__) At the top of the module and subsequent: LOG.info(‘Spam and eggs are tasty!’) from anywhere in the file typically gets me to where I want to … Read more
You can get the logger from the SparkContext object: log4jLogger = sc._jvm.org.apache.log4j LOGGER = log4jLogger.LogManager.getLogger(__name__) LOGGER.info(“pyspark script logger initialized”)
The logging module already has partial support for what you want to do. Do this: log.debug(“Some message: a=%s b=%s”, a, b) … instead of this: log.debug(“Some message: a=%s b=%s” % (a, b)) The logging module is smart enough to not produce the complete log message unless the message actually gets logged somewhere. To apply this … Read more
Change the line to this: handler = SysLogHandler(address=”/dev/log”) This works for me import logging import logging.handlers my_logger = logging.getLogger(‘MyLogger’) my_logger.setLevel(logging.DEBUG) handler = logging.handlers.SysLogHandler(address=”/dev/log”) my_logger.addHandler(handler) my_logger.debug(‘this is debug’) my_logger.critical(‘this is critical’)
The problem is that calling getLogger without arguments returns the root logger so when you set the level to logging.DEBUG you are also setting the level for other modules that use that logger. You can solve this by simply not using the root logger. To do this just pass a name as argument, for example … Read more
Have you looked at python docs site section describing Implementing structured logging that explain how python built-in logger can be utilized for structured logging? Below is a simple example as listed on above site . import json import logging class StructuredMessage(object): def __init__(self, message, **kwargs): self.message = message self.kwargs = kwargs def __str__(self): return ‘%s … Read more
You have two options: Open a logfile and replace sys.stdout with it, not a function: log = open(“myprog.log”, “a”) sys.stdout = log >>> print(“Hello”) >>> # nothing is printed because it goes to the log file instead. Replace print with your log function: # If you’re using python 2.x, uncomment the next line #from __future__ … Read more
Just implement a subclass of logging.Filter: http://docs.python.org/library/logging.html#filter-objects. It will have one method, filter(record), that examines the log record and returns True to log it or False to discard it. Then you can install the filter on either a Logger or a Handler by calling its addFilter(filter) method. Example: class NoParsingFilter(logging.Filter): def filter(self, record): return not … Read more
You cannot use new-style formatting when using the logging module; use %s instead of {}. logging.info(‘date=%s’, date) The logging module uses the old-style % operator to format the log string. See the debug method for more detail. If you really want to use str.format() string formatting, consider using custom objects that apply the formatting ‘late’, … Read more
You have to define which type of exception you want to catch. So write except Exception, e: instead of except, e: for a general exception (that will be logged anyway). Other possibility is to write your whole try/except code this way: try: with open(filepath,’rb’) as f: con.storbinary(‘STOR ‘+ filepath, f) logger.info(‘File successfully uploaded to ‘+ … Read more