Missalignment with inline-block (other elements pushed down)
http://jsfiddle.net/PMRQ5/1/ Add vertical-align: top or vertical-align: bottom to the box, depends on what you want.
http://jsfiddle.net/PMRQ5/1/ Add vertical-align: top or vertical-align: bottom to the box, depends on what you want.
Since kafka 0.11.0.0 you can use the script kafka-consumer-groups.sh Example from this answer kafka-consumer-groups.sh –bootstrap-server kafka-host:9092 –group my-group –reset-offsets –to-earliest –all-topics –execute Other options listed in the KIP-122: Add Reset Consumer Group Offsets tooling .———————-.———————————————–.———————————————————————————————————————————————-. | Scenario | Arguments | Example | :———————-+———————————————–+———————————————————————————————————————————————-: | Reset to Datetime | –to-datetime YYYY-MM-DDTHH:mm:SS.sss±hh:mm | Reset to first offset … Read more
This is what jQuery API Doc says about .offset(): Get the current coordinates of the first element, or set the coordinates of every element, in the set of matched elements, relative to the document. This is what MDN Web API says about .offsetTop: offsetTop returns the distance of the current element relative to the top … Read more
I just noticed that the placement option could either be a string or a function returning a string that makes the calculation each time you click on a popover-able link. This makes it real easy to replicate what you did without the initial $.each function: var options = { placement: function (context, source) { var … Read more
Prior to 12.1, Oracle does not support the LIMIT or OFFSET keywords. If you want to retrieve rows N through M of a result set, you’d need something like: SELECT a.* FROM (SELECT b.*, rownum b_rownum FROM (SELECT c.* FROM some_table c ORDER BY some_column) b WHERE rownum <= <<upper limit>>) a WHERE b_rownum >= … Read more
R.. is correct in his answer to the second part of your question: this code is not advised when using a modern C compiler. But to answer the first part of your question, what this is actually doing is: ( (int)( // 4. &( ( // 3. (a*)(0) // 1. )->b ) // 2. ) … Read more
var cumulativeOffset = function(element) { var top = 0, left = 0; do { top += element.offsetTop || 0; left += element.offsetLeft || 0; element = element.offsetParent; } while(element); return { top: top, left: left }; }; (Method shamelessly stolen from PrototypeJS; code style, variable names and return value changed to protect the innocent)
element.offsetLeft and element.offsetTop give an element’s position with respect to its offsetParent (which is the nearest parent element with a position of relative or absolute.)
— Shameless plug — I have added this function to a library I created vanillajs-browser-helpers: https://github.com/Tokimon/vanillajs-browser-helpers/blob/master/inView.js ——————————- Well BenM stated, you need to detect the height of the viewport + the scroll position to match up with your top position. The function you are using is ok and does the job, though its a bit … Read more
You could just use CSS without any javascript. Give your anchor a class: <a class=”anchor” id=”top”></a> You can then position the anchor an offset higher or lower than where it actually appears on the page, by making it a block element and relatively positioning it. -250px will position the anchor up 250px a.anchor { display: … Read more