int8_t is a typedef for an integer type with the required characteristics: pure 2’s-complement representation, no padding bits, size of exactly 8 bits. For most (perhaps all) compilers, that means it’s going to be a typedef for signed char.(Because of a quirk in the definition of the term signed integer type, it cannot be a … Read more
Why does not give it out a compilation error or a runtime Exception? Because the language specification mandates that arithmetic on primitive types is modulo 2^width, so -1 becomes 2^16-1 as a char. In the section on integer operations, it is stated that The built-in integer operators do not indicate overflow or underflow in any … Read more
Xcode 9 • Swift 4 or later extension UIColor { convenience init?(hexaRGB: String, alpha: CGFloat = 1) { var chars = Array(hexaRGB.hasPrefix(“#”) ? hexaRGB.dropFirst() : hexaRGB[…]) switch chars.count { case 3: chars = chars.flatMap { [$0, $0] } case 6: break default: return nil } self.init(red: .init(strtoul(String(chars[0…1]), nil, 16)) / 255, green: .init(strtoul(String(chars[2…3]), nil, 16)) … Read more
Big integers aren’t actually limited to 20 digits, they’re limited to the numbers that can be expressed in 64 bits (for example, the number 99,999,999,999,999,999,999 is not a valid big integer despite it being 20 digits long). The reason you have this limitation is that native format integers can be manipulated relatively fast by the … Read more
Have a look at strtol(), it can tell you about invalid parts of the string by pointer return. And beware of enthusiastic example code.. see the man page for comprehensive error-handling.
Two things: Specify the keyboard type to only show the numeric keypad. So, set the keyboardType to .numberPad. This, however is not enough to stop the user from entering invalid characters in the text field. For example, the user is still able to paste text or switch keyboards when using an iPad. Specify the text … Read more
They are being divided in integer arithmetics. So dividing integer a by integer b you get how many times b fits into a. Also a % b will give you a remainder of a division. So (a / b ) * b + a % b = a
That’s because integers don’t have values for +/-Inf, NaN, and don’t allow division by 0, while floats do have those special values.
There are two problems: Int is a 64-bit integer on 64-bit platforms, your input data has only 32-bit. Int uses a little-endian representation on all current Swift platforms, your input is big-endian. That being said the following would work: let array : [UInt8] = [0, 0, 0, 0x0E] var value : UInt32 = 0 let … Read more
Do you want to convert ints to chars?: int yourInt = 33; char ch = (char) yourInt; System.out.println(yourInt); System.out.println(ch); // Output: // 33 // ! Or do you want to convert ints to Strings? int yourInt = 33; String str = String.valueOf(yourInt); Or what is it that you mean?