Show a one to many relationship as 2 columns – 1 unique row (ID & comma separated list)
I believe that the answer you need is a user-defined aggregate, similar to this one: CREATE FUNCTION gc_init(dummy VARCHAR(255)) RETURNING LVARCHAR; RETURN ”; END FUNCTION; CREATE FUNCTION gc_iter(result LVARCHAR, value VARCHAR(255)) RETURNING LVARCHAR; IF result=”” THEN RETURN TRIM(value); ELSE RETURN result || ‘,’ || TRIM(value); END IF; END FUNCTION; CREATE FUNCTION gc_comb(partial1 LVARCHAR, partial2 LVARCHAR) … Read more