So, can somebody please help me understand why leveraging the same overload inside of those other methods is failing with that error? Precisely because you’re using a dynamic value (param) as one of the arguments. That means it will use dynamic dispatch… but dynamic dispatch isn’t supported for extension methods. The solution is simple though: … Read more
In my case it was a project defined using Target Framework: “.NET Framework 4.0 Client Profile ” that tried to reference dll projects defined using Target Framework: “.NET Framework 4.0”. Once I changed the project settings to use Target Framework: “.NET Framework 4.0” everything was built nicely. Right Click the project->Properties->Application->Target Framework
Your problem is a side-effect of Generalized Target-type Inference, an improvement in Java 8. What is Target-type Inference Let’s take your example method, public static <R> R get(String d) { return (R)d; } Now, in the method above, the generic parameter R cannot be resolved by the compiler because there’s no parameter with R. So, … Read more
You are likely importing java.awt.List. You should instead import java.util.List, which is a parameterized type.
I was having the same problem and noticed that all of the undeclared identifiers were declared in files that were in my pch file. With this in mind I deleted one of the #import lines from the pch file and recompiled which failed as expected. I then put the deleted line back in, recompiled and … Read more
You seem to be saying that the code you are showing doesn’t actually produce the compiler error that you are having a problem with. So we can only guess. Here are some possibilities: You could have forgot to include problemclass.h from the file where you are using ProblemClass. You could have misspelled the name of … Read more
Generic functions in TypeScript act as a function representing every possible specification of its generic type parameters, since it’s the caller of the function that specifies the type parameter, not the implementer: type GenericFunction = <T>(x: T) => T; const cantDoThis: GenericFunction = (x: string) => x.toUpperCase(); // error! // doesn’t work for every T … Read more
Yes, it is possible to avoid reporting undefined references – using –unresolved-symbols linker option. g++ mm.cpp -Wl,–unresolved-symbols=ignore-in-object-files From man ld –unresolved-symbols=method Determine how to handle unresolved symbols. There are four possible values for method: ignore-all Do not report any unresolved symbols. report-all Report all unresolved symbols. This is the default. ignore-in-object-files Report unresolved symbols that … Read more
Seeing from your G++ version, you need to update it badly. C++11 has only been available since G++ 4.3. The most recent version is 4.7. In versions pre-G++ 4.7, you’ll have to use -std=c++0x, for more recent versions you can use -std=c++11.
As Selman22 said, you are overriding the default object.Equals method, which accepts an object obj and not a safe compile time type. In order for that to happen, make your type implement IEquatable<Box>: public class Box : IEquatable<Box> { double height, length, breadth; public static bool operator ==(Box obj1, Box obj2) { if (ReferenceEquals(obj1, obj2)) … Read more