Use a “closure”: $(edit_link).click(function(){ return changeViewMode(myvar); }); This creates an anonymous temporary function wrapper that knows about the parameter and passes it to the actual callback implementation.
You are basically creating a closure. In computer science, a closure is a first-class function with free variables that are bound in the lexical environment. Such a function is said to be “closed over” its free variables. Related reading: Closures: why are they so useful? A closure is simply a more convenient way to give … Read more
From JavaScript Closures Two one-sentence summaries: A closure is the local variables for a function – kept alive after the function has returned, or A closure is a stack-frame which is not deallocated when the function returns. (as if a ‘stack-frame’ were malloc’ed instead of being on the stack!) A very good article on closures … Read more
The easiest way of finding out how it’s implemented is to try it. Write some code which uses a captured variable, compile it, then look at it in Reflector. Note that it’s the variable which is captured, not the value. That’s one of the big differences between Java and C# in this area. The basic … Read more
You’re close… Why does item have a value of ‘item3’? Doesn’t the for loop end when i becomes 3? Yes. If it ends shouldn’t item still be ‘item2’? Nope. This example is a little tricky. During the last iteration of the loop, i is 2, but it references the 3rd element of the list array, … Read more
You say: From what I understand the setup here is: self —> queue self <— block The queue is merely a shell/wrapper for the block. Which is why even if I nil the queue, the block will continue its execution. They’re independent. The fact that self happens to have a strong reference to the queue … Read more
I wrote a curried function whose valueOf() method and function context (this) are bound with the sum no matter how many arguments are passed each time. /* add function */ let add = function add(…args) { const sum = args.reduce((acc, val) => acc + val, this); const chain = add.bind(sum); chain.valueOf = () => sum; … Read more
This is a known issue regarding how the function traits are inferred through Deref. As a workaround, you need to explicitly get a mutable reference by doing a mutable reborrow: let mut t = Foo; (&mut *t)(); or by calling DerefMut::deref_mut: let mut t = Foo; t.deref_mut()();
This has more to do with lambdas than threading. A lambda captures the reference to a variable, not the variable’s value. This means that when you try to use i in your code, its value will be whatever was stored in i last. To avoid this, you should copy the variable’s value to a local … Read more
Rust 1.26 Closures implement both Copy and Clone if all of the captured variables do. You can rewrite your code to use generics instead of a boxed trait object to be able to clone it: use std::thread; #[derive(Clone)] struct WithCall<F> { fp: F, } impl<F> WithCall<F> where F: Fn(i8, i8) -> i8, { pub fn … Read more