The problem lies in your base case. “The height of a tree is the length of the path from the root to the deepest node in the tree. A (rooted) tree with only a node (the root) has a height of zero.” – Wikipedia If there is no node, you want to return -1 not … Read more
How to fix remove in RedBlackTree implementation?
Here is a quick example of a binary insert: class Node: def __init__(self, val): self.l_child = None self.r_child = None self.data = val def binary_insert(root, node): if root is None: root = node else: if root.data > node.data: if root.l_child is None: root.l_child = node else: binary_insert(root.l_child, node) else: if root.r_child is None: root.r_child = … Read more
Binary tree: Tree where each node has up to two leaves 1 / \ 2 3 Binary search tree: Used for searching. A binary tree where the left child contains only nodes with values less than the parent node, and where the right child only contains nodes with values greater than or equal to the … Read more
node structure and insertion We start with a simple node structure, but notice the left and right properties can be set at the time of construction – # btree.py class node: def __init__(self, data, left=None, right=None): self.data = data self.left = left self.right = right Recursion is a functional heritage and so using it with … Read more
Do you need to know all the details of DST transition yourself? or do you just need to know when is 9:00 am in a given timezone? If it’s the latter, PHP can use your operating system’s timezone database to do that for you. The strtotime() function is remarkably good at “figuring out” what you … Read more
The general way depends on whether you have a parent link in your nodes or not. If you store the parent link Then you pick: The leftmost child of the right child, if your current node has a right child. If the right child has no left child, the right child is your inorder successor. … Read more
Summary Type BST (*) Heap Insert average log(n) 1 Insert worst log(n) log(n) or n (***) Find any worst log(n) n Find max worst 1 (**) 1 Create worst n log(n) n Delete worst log(n) log(n) All average times on this table are the same as their worst times except for Insert. *: everywhere in … Read more
Actually that is the mistake everybody does in an interview. Leftchild must be checked against (minLimitof node,node.value) Rightchild must be checked against (node.value,MaxLimit of node) IsValidBST(root,-infinity,infinity); bool IsValidBST(BinaryNode node, int MIN, int MAX) { if(node == null) return true; if(node.element > MIN && node.element < MAX && IsValidBST(node.left,MIN,node.element) && IsValidBST(node.right,node.element,MAX)) return true; else return false; … Read more
The simplest solution for this is maintaining a min heap of max size 5000. Every time a new number arrives – check if the heap is smaller then 5000, if it is – add it. If it is not – check if the minimum is smaller then the new element, and if it is, pop … Read more