It doesn’t make sense to dereference a void pointer. How will the compiler interpret the memory that the pointer is pointing to? You need to cast the pointer to a proper type first:
int x = *(int*)lVptr;
It doesn’t make sense to dereference a void pointer. How will the compiler interpret the memory that the pointer is pointing to? You need to cast the pointer to a proper type first:
int x = *(int*)lVptr;