# Bitwise XOR of hexadecimal numbers

Whoa. You’re really over-complicating it by a very long distance. Try:

``````>>> print(hex(0x12ef ^ 0xabcd))
0xb922
``````

You seem to be ignoring these handy facts, at least:

• Python has native support for hexadecimal integer literals, with the `0x` prefix.
• “Hexadecimal” is just a presentation detail; the arithmetic is done in binary, and then the result is printed as hex.
• There is no connection between the format of the inputs (the hexadecimal literals) and the output, there is no such thing as a “hexadecimal number” in a Python variable.
• The `hex()` function can be used to convert any number into a hexadecimal string for display.

If you already have the numbers as strings, you can use the `int()` function to convert to numbers, by providing the expected base (16 for hexadecimal numbers):

``````>>> print(int("12ef", 16))
4874
``````

So you can do two conversions, perform the XOR, and then convert back to hex:

``````>>> print(hex(int("12ef", 16) ^ int("abcd", 16)))
0xb922
``````