Use a map with word as a key and count as value, somthing like this Map<String, Integer> map = new HashMap<>(); for (String w : words) { Integer n = map.get(w); n = (n == null) ? 1 : ++n; map.put(w, n); } if you are not allowed to use java.util then you can sort … Read more
WordNet database might be helpful. I once worked on a Firefox add-on which deals with words and all kinds of simple to complicated associations between them and stuff. Looks like WordNet will be very much useful to you. Here it is in MySQL format. And this one (web-archived link) uses Wordnet v3.0 data, rather than … Read more
Try this: import re mystr=”This is a string, with words!” wordList = re.sub(“[^\w]”, ” “, mystr).split() How it works: From the docs : re.sub(pattern, repl, string, count=0, flags=0) Return the string obtained by replacing the leftmost non-overlapping occurrences of pattern in string by the replacement repl. If the pattern isn’t found, string is returned unchanged. … Read more
Try grep -o: grep -oh “\w*th\w*” * Edit: matching from Phil’s comment. From the docs: -h, –no-filename Suppress the prefixing of file names on output. This is the default when there is only one file (or only standard input) to search. -o, –only-matching Print only the matched (non-empty) parts of a matching line, with each … Read more
What you need is word-wrap: break-word;, this property will force the non spaced string to break inside the div Demo div { width: 20px; word-wrap: break-word; }