It’s all in your things.size() type. It isn’t int, but size_t (it exists in C++, not in C) which equals to some “usual” unsigned type, i.e. unsigned int for x86_32. Operator “less” (<) cannot be applied to two operands of different sign. There’s just no such opcodes, and standard doesn’t specify, whether compiler can make … Read more
Reversing the bits in a word is annoying and it’s easier just to output them in reverse order. E.g., void write_u32(uint32_t x) { int i; for (i = 0; i < 32; ++i) putchar((x & ((uint32_t) 1 << (31 – i)) ? ‘1’ : ‘0’); } Here’s the typical solution to reversing the bit order: … Read more
Assign a int -1 to an unsigned: As -1 does not fit in the range [0…UINT_MAX], multiples of UINT_MAX+1 are added until the answer is in range. Evidently UINT_MAX is pow(2,32)-1 or 429496725 on OP’s machine so a has the value of 4294967295. unsigned int a = -1; The “%x”, “%u” specifier expects a matching … Read more
The “%d” format is for (signed) int values. If you use it with an unsigned value, it could print something other than the actual value. Use “%u” to see the actual value, or %x to see it in hexadecimal. In the declaration unsigned int x = -1; the expression -1 is of type int, and … Read more
The following is how standard (ISO 14882) explains abort -1 > sizeof(int) Relational operator `>’ is defined in 5.9 (expr.rel/2) The usual arithmetic conversions are performed on operands of arithmetic or enumeration type. … The usual arithmetic conversions is defined in 5 (expr/9) … The pattern is called the usual arithmetic conversions, which are defined … Read more
Something like this? int x = -1; long y = x & 0x00000000ffffffffL; Or am I missing something? public static long getUnsignedInt(int x) { return x & 0x00000000ffffffffL; }
The number itself is always interpreted as a non-negative number. Hexadecimal constants don’t have a sign or any inherent way to express a negative number. The type of the constant is the first one of these which can represent their value: int unsigned int long int unsigned long int long long int unsigned long long … Read more
if it is use to represent non negative value so why we not using unsigned int instead of size_t Because unsigned int is not the only unsigned integer type. size_t could be any of unsigned char, unsigned short, unsigned int, unsigned long or unsigned long long, depending on the implementation. Second question is that size_t … Read more
Why C++ doesn’t have support for unsigned floats is because there is no equivalent machine code operations for the CPU to execute. So it would be very inefficient to support it. If C++ did support it, then you would be sometimes using an unsigned float and not realizing that your performance has just been killed. … Read more
unsigned is a modifier which can apply to any integral type (char, short, int, long, etc.) but on its own it is identical to unsigned int.