Using regular expressions – documentation for further reference import re text=”gfgfdAAA1234ZZZuijjk” m = re.search(‘AAA(.+?)ZZZ’, text) if m: found = m.group(1) # found: 1234 or: import re text=”gfgfdAAA1234ZZZuijjk” try: found = re.search(‘AAA(.+?)ZZZ’, text).group(1) except AttributeError: # AAA, ZZZ not found in the original string found = ” # apply your error handling # found: 1234
You’re correct! ‘example'[3:4] and ‘example'[3] are fundamentally different, and slicing outside the bounds of a sequence (at least for built-ins) doesn’t cause an error. It might be surprising at first, but it makes sense when you think about it. Indexing returns a single item, but slicing returns a subsequence of items. So when you try … Read more
You can use Marcus’s answer (* wildcards) outside a case statement, too, if you use double brackets: string=’My long string’ if [[ $string == *”My long”* ]]; then echo “It’s there!” fi Note that spaces in the needle string need to be placed between double quotes, and the * wildcards should be outside. Also note … Read more
>>> x = “Hello World!” >>> x[2:] ‘llo World!’ >>> x[:2] ‘He’ >>> x[:-2] ‘Hello Worl’ >>> x[-2:] ‘d!’ >>> x[2:-2] ‘llo Worl’ Python calls this concept “slicing” and it works on more than just strings. Take a look here for a comprehensive introduction.
How do I check if a string contains a specific word?
Use the in operator: if “blah” not in somestring: continue
ECMAScript 6 introduced String.prototype.includes: const string = “foo”; const substring = “oo”; console.log(string.includes(substring)); // true includes doesn’t have Internet Explorer support, though. In ECMAScript 5 or older environments, use String.prototype.indexOf, which returns -1 when a substring cannot be found: var string = “foo”; var substring = “oo”; console.log(string.indexOf(substring) !== -1); // true