address = “123 north anywhere street” for word, initial in {“NORTH”:”N”, “SOUTH”:”S” }.items(): address = address.replace(word.lower(), initial) print address nice and concise and readable too.
Try this: line.Replace(“\”,\””, “;”)
address = “123 north anywhere street” for word, initial in {“NORTH”:”N”, “SOUTH”:”S” }.items(): address = address.replace(word.lower(), initial) print address nice and concise and readable too.
You need two backslashes before the dot, one to escape the slash so it gets through, and the other to escape the dot so it becomes literal. Forward slashes and asterisk are treated literal. str=xpath.replaceAll(“\\.”, “/*/”); //replaces a literal . with /*/ http://docs.oracle.com/javase/7/docs/api/java/lang/String.html#replaceAll(java.lang.String,%20java.lang.String)
one solution without regex: var expDate=”2016-03″; var formatExp = expDate.split(‘-‘).reverse().join(“https://stackoverflow.com/”); //result is 03/2016 alert(‘result: ‘ + formatExp); var formatExpShort = expDate.substring(2).split(‘-‘).reverse().join(“https://stackoverflow.com/”); //result is 03/16 alert(‘result short: ‘ + formatExpShort);
Like this: str_replace(array(‘:’, ‘\\’, “https://stackoverflow.com/”, ‘*’), ‘ ‘, $string); Or, in modern PHP (anything from 5.4 onwards), the slighty less wordy: str_replace([‘:’, ‘\\’, “https://stackoverflow.com/”, ‘*’], ‘ ‘, $string);
First difference: An interesting example of a different behaviour between strtr and str_replace is in the comments section of the PHP Manual: <?php $arrFrom = array(“1″,”2″,”3″,”B”); $arrTo = array(“A”,”B”,”C”,”D”); $word = “ZBB2″; echo str_replace($arrFrom, $arrTo, $word); ?> I would expect as result: “ZDDB” However, this return: “ZDDD” (Because B = D according to our array) … Read more
You could use a preg_match_all(…): $text=”Lorem ipsum “dolor sit amet” consectetur “adipiscing \\”elit” dolor”; preg_match_all(“https://stackoverflow.com/”(?:\\\\.|[^\\\\”])*”|\S+/’, $text, $matches); print_r($matches); which will produce: Array ( [0] => Array ( [0] => Lorem [1] => ipsum [2] => “dolor sit amet” [3] => consectetur [4] => “adipiscing \”elit” [5] => dolor ) ) And as you can see, … Read more
You want to use regular expressions. The \b matches a word boundary. $text = preg_replace(‘/\bHello\b/’, ‘NEW’, $text); If $text contains UTF-8 text, you’ll have to add the Unicode modifier “u”, so that non-latin characters are not misinterpreted as word boundaries: $text = preg_replace(‘/\bHello\b/u’, ‘NEW’, $text);
std::string doesn’t contain such function but you could use stand-alone replace function from algorithm header. #include <algorithm> #include <string> void some_func() { std::string s = “example string”; std::replace( s.begin(), s.end(), ‘x’, ‘y’); // replace all ‘x’ to ‘y’ }