I can’t answer the “should you” part of whether to use refs for this instead other than if you do, you don’t need those id values unless you use them for something else. But here’s how you would: Use useRef(null) to create the ref. const activeSlideRef = useRef(null); Put it on the Slide that’s currently … Read more
Note: This code is untested Define a record for your refCursor return type, call it rec. For example: TYPE MyRec IS RECORD (col1 VARCHAR2(10), col2 VARCHAR2(20), …); –define the record rec MyRec; — instantiate the record Once you have the refcursor returned from your procedure, you can add the following code where your comments are … Read more
A leading slash tells the browser to start at the root directory. If you don’t have the leading slash, you’re referencing from the current directory. If you add two dots before the leading slash, it means you’re referencing the parent of the current directory. Take the following folder structure notice: the ROOT checkmark is green, … Read more
For ‘out’, the following seems to work for me. public interface IService { void DoSomething(out string a); } [TestMethod] public void Test() { var service = new Mock<IService>(); var expectedValue = “value”; service.Setup(s => s.DoSomething(out expectedValue)); string actualValue; service.Object.DoSomething(out actualValue); Assert.AreEqual(expectedValue, actualValue); } I’m guessing that Moq looks at the value of ‘expectedValue’ when you … Read more
Short answer: read my article on argument passing. Long answer: when a reference type parameter is passed by value, only the reference is passed, not a copy of the object. This is like passing a pointer (by value) in C or C++. Changes to the value of the parameter itself won’t be seen by the … Read more
ref tells the compiler that the object is initialized before entering the function, while out tells the compiler that the object will be initialized inside the function. So while ref is two-ways, out is out-only.
Pass a ref if you want to change what the object is: TestRef t = new TestRef(); t.Something = “Foo”; DoSomething(ref t); void DoSomething(ref TestRef t) { t = new TestRef(); t.Something = “Not just a changed t, but a completely different TestRef object”; } After calling DoSomething, t does not refer to the original … Read more