Simply create a new object and pass the required arguments in the constructor. Point position= new Point((int) (Math.random()*(max – min)),(int) (Math.random() *(max – min))); Point endPosition = new Point(position.x+2, position.y+3);
Use the quadratic Bézier formula, found, for instance, on the Wikipedia page for Bézier Curves: In pseudo-code, that’s t = 0.5; // given example value x = (1 – t) * (1 – t) * p[0].x + 2 * (1 – t) * t * p[1].x + t * t * p[2].x; y = (1 … Read more
Try using the norm function from numpy.linalg d = norm(np.cross(p2-p1, p1-p3))/norm(p2-p1)
As Mads pointed out, in order to catch most accesses through null pointers, Unix-like systems tend to make the page at address zero “unmapped”. Thus, accesses immediately trigger a CPU exception, in other words a segfault. This is quite better than letting the application go rogue. The exception vector table, however, can be at any … Read more
I have found a very good solution to this from MapBox called Polylabel. The full source is available on their Github too. Essentially it tries to find the visual centre of the polygon as T Austin said. Certain details suggest this may be a practical solution: Unfortunately, calculating [the ideal solution ] is both complex … Read more
There are 72 points per inch; if it is sufficient to assume 96 pixels per inch, the formula is rather simple: points = pixels * 72 / 96 There is a way to get the configured pixels per inch of your display in Windows using GetDeviceCaps. Microsoft has a guide called “Developing DPI-Aware Applications”, look … Read more
You do not need to have any objects in your scene to do this. You already know the camera position. Using vector.unproject( camera ) you can get a ray pointing in the direction you want. You just need to extend that ray, from the camera position, until the z-coordinate of the tip of the ray … Read more