When calling a PHP script from the command line you can use $argc to find out how many parameters are passed and $argv to access them. For example running the following script: <?php var_dump($argc); //number of arguments passed var_dump($argv); //the arguments passed ?> Like this:- php script.php arg1 arg2 arg3 Will give the following output … Read more
class Foo (object): # ^class name #^ inherits from object bar = “Bar” #Class attribute. def __init__(self): # #^ The first variable is the class instance in methods. # # This is called “self” by convention, but could be any name you want. #^ double underscore (dunder) methods are usually special. This one # gets … Read more
I must confess I use to put my parameters as query string parameters in the url : during init : url: ‘/upload.aspx?id=’+Id, or later : upldr.settings.url = upldr.settings.url + ‘&token=’ + myToken; It works fine. Hope this will help
If you construct a string such as -t foo and pass it via a variable to an external program, it is passed as a single, double-quoted argument (that is, donet will literally see “-t foo” on its command line) – and therefore won’t be recognized as parameter name-value combination. You must pass -t and foo … Read more
Problem is closures, since JS doesn’t have block scope (only function scope) i is not what you think because the event function creates another scope so by the time you use i it’s already the latest value from the for loop. You need to keep the value of i. Using an IIFE: for (var i=0; … Read more
You can’t use a single parameter for a list of values in this way. But there may be database-specific ways to achieve what you want. For example, with SQL Server 2005 or later you could create a table-valued function to split your string parameter, something like: CREATE FUNCTION dbo.F_Split ( @InputString VARCHAR(MAX) ,@Separator VARCHAR(MAX) ) … Read more
Java always passes arguments by value, NOT by reference. In your example, you are still passing obj by its value, not the reference itself. Inside your method changeName, you are assigning another (local) reference, obj, to the same object you passed it as an argument. Once you modify that reference, you are modifying the original … Read more
That’s an old-style function declaration. This declaration: void foo(); declares that foo is a function returning void that takes an unspecified but fixed number and type(s) of arguments. It doesn’t mean that calls with arbitrary arguments are valid; it means that the compiler can’t diagnose incorrect calls with the wrong number or type of arguments. … Read more
SQL NOT IN works with sets. Since you are passing an array, use <> ALL. You have to be careful not to involve any NULL values with such an expression, because NULL <> anything never evaluates to TRUE and therefore never qualifies in a WHERE clause. Your function could look like this: CREATE OR REPLACE … Read more
After loading the controller with the FXMLLoader, it is possible to call for members of said controller before the show() method is invoked. One must get the reference to the controller just invoked and call a set() method from there (or access the attribute directly, if defined public). From the example, let us suppose that … Read more