You can try this: library(dplyr) ranges %>% arrange(start) %>% group_by(g = cumsum(cummax(lag(stop, default = first(stop))) < start)) %>% summarise(start = first(start), stop = max(stop)) # A tibble: 2 × 3 # g start stop # <int> <dbl> <dbl> #1 0 65.72000 87.75625 #2 1 89.61625 104.94062
Just set a background color to your <fragment /> in XML file. Solves the issue.
Use a capturing group inside a lookahead. The lookahead captures the text you’re interested in, but the actual match is technically the zero-width substring before the lookahead, so the matches are technically non-overlapping: import re s = “123456789123456789” matches = re.finditer(r'(?=(\d{10}))’,s) results = [int(match.group(1)) for match in matches] # results: # [1234567891, # 2345678912, # … Read more
Simply because in both cases the combination of colors is not the same due to how opacity of the top layer affect the color of the bottom layer. For the first case, you see 50% of blue and 50% of transparent in the top layer. Through the transparent part, you see 50% of red color … Read more
findall doesn’t yield overlapping matches by default. This expression does however: >>> re.findall(r'(?=(\w\w))’, ‘hello’) [‘he’, ‘el’, ‘ll’, ‘lo’] Here (?=…) is a lookahead assertion: (?=…) matches if … matches next, but doesn’t consume any of the string. This is called a lookahead assertion. For example, Isaac (?=Asimov) will match ‘Isaac ‘ only if it’s followed … Read more
Use a capturing group inside a lookahead. The lookahead captures the text you’re interested in, but the actual match is technically the zero-width substring before the lookahead, so the matches are technically non-overlapping: import re s = “123456789123456789” matches = re.finditer(r'(?=(\d{10}))’,s) results = [int(match.group(1)) for match in matches] # results: # [1234567891, # 2345678912, # … Read more