I am pretty sure you want: UIApplication.sharedApplication().openURL(NSURL(string: “tel://9809088798”)!) (note that in your question text, you put tel//:, not tel://). NSURL’s string init expects a well-formed URL. It will not turn a bunch of numbers into a telephone number. You sometimes see phone-number detection in UIWebView, but that’s being done at a higher level than NSURL. … Read more
This is listed as a known issue in the 10.3 release notes. https://developer.apple.com/library/content/releasenotes/General/RN-iOSSDK-10.3/ openURL When a third party application invokes openURL: on a tel://, facetime://, or facetime-audio:// URL, iOS displays a prompt and requires user confirmation before dialing. It is also listed in the Security content of the 10.3 update, so I’m assuming this a … Read more
The lee answer is absolutely correct for iOS prior to 8. In iOS 9+ you must whitelist any URL schemes your App wants to query in Info.plist under the LSApplicationQueriesSchemes key (an array of strings):