I assume you are using ISO 8601 week numbers, and want the first day of a ISO 8601 week so that e.g. Week 1 of 2011 returns January 3 2011. strtotime can do this out of the box using the {YYYY}W{WW} format: echo date(“Y-m-d”, strtotime(“2011W01”)); // 2011-01-03 Note that the week number needs to be … Read more
Instead of plotting datenums, use the associated datetimes. import numpy as np import matplotlib.pyplot as plt import matplotlib.dates as mdates import datetime as DT import time dates = [DT.datetime(1978, 7, 7), DT.datetime(1980, 9, 26), DT.datetime(1983, 8, 1), DT.datetime(1985, 8, 8)] y = [0.00134328779552718, 0.00155187668863844, 0.0039431374327427, 0.00780037563783297] yerr = [0.0000137547160254577, 0.0000225670232594083, 0.000105623642510075, 0.00011343121508] x = mdates.date2num(dates) … Read more
Today, using PHP’s DateTime objects is better: <?php $ddate = “2012-10-18”; $date = new DateTime($ddate); $week = $date->format(“W”); echo “Weeknummer: $week”; It’s because in mktime(), it goes like this: mktime(hour, minute, second, month, day, year); Hence, your order is wrong. <?php $ddate = “2012-10-18”; $duedt = explode(“-“, $ddate); $date = mktime(0, 0, 0, $duedt[1], $duedt[2], … Read more
Dates in the m/d/y or d-m-y formats are disambiguated by looking at the separator between the various components: if the separator is a slash (/), then the American m/d/y is assumed; whereas if the separator is a dash (-) or a dot (.), then the European d-m-y format is assumed. Check more here. Use the … Read more