I assume you want to be able to use step-through debugging from Eclipse. You can just run the classes externally by setting the built classes in the bin directories on the JRE classpath. java -cp workspace\p1\bin;workspace\p2\bin foo.Main You can debug using the remote debugger and taking advantage of the class files built in your project. … Read more
Place your text file in the /assets directory under the Android project. Use AssetManager class to access it. AssetManager am = context.getAssets(); InputStream is = am.open(“test.txt”); Or you can also put the file in the /res/raw directory, where the file will be indexed and is accessible by an id in the R file: InputStream is … Read more
Just implement Serializable If you’re getting a NotSerializableException like follows, java.io.NotSerializableException: bean.ProjectAreaBean then it simply means that the class as identified by the fully qualified name in the exception message (which is bean.ProjectAreaBean in your case) does not implement the Serializable interface while it is been expected by the code behind. Fixing it is relatively … Read more
CodeSource src = MyClass.class.getProtectionDomain().getCodeSource(); if (src != null) { URL jar = src.getLocation(); ZipInputStream zip = new ZipInputStream(jar.openStream()); while(true) { ZipEntry e = zip.getNextEntry(); if (e == null) break; String name = e.getName(); if (name.startsWith(“path/to/your/dir/”)) { /* Do something with this entry. */ … } } } else { /* Fail… */ } Note that … Read more
Code : public class JavaApplication { public static void main(String[] args) { System.out.println(“Working Directory = ” + System.getProperty(“user.dir”)); } } This will print the absolute path of the current directory from where your application was initialized. Explanation: From the documentation: java.io package resolve relative pathnames using current user directory. The current directory is represented as … Read more