Try this: $(‘document’).ready(function() { $(document).scroll(function(){ if(document.documentElement.clientHeight + $(document).scrollTop() >= document.body.offsetHeight )$(document).scrollTop(0); }); });
You can use the second argument of iter(), to call a function repeatedly until its return value matches that argument. This would loop forever as 1 will never be equal to 0 (which is the return value of int()): for _ in iter(int, 1): pass If you wanted an infinite loop using numbers that are … Read more
The odds, i.e. 2-coprimes, are generated by “rolling the wheel” [2], i.e. by repeated additions of 2, starting from the initial value of 3 (similarly from 5, 7, 9, …), n=3; n+=2; n+=2; n+=2; … # wheel = [2] 3 5 7 9 The 2-3-coprimes are generated by repeated additions of 2, then 4, and … Read more
In your last else block, you need to clear the ‘w’ or other invalid input from the Scanner. You can do this by calling next() on the Scanner and ignoring its return value to throw away that invalid input, as follows: else { System.out.println(“You have entered an invalid input. Try again.”); in.next(); }
Your first definition, kart xs ys = [(x,y) | x <- xs, y <- ys], is equivalent to kart xs ys = xs >>= (\x -> ys >>= (\y -> [(x,y)])) where (x:xs) >>= g = g x ++ (xs >>= g) (x:xs) ++ ys = x : (xs ++ ys) are sequential operations. Redefine … Read more
In Python, you can do: test = float(“inf”) In Python 3.5, you can do: import math test = math.inf And then: test > 1 test > 10000 test > x Will always be true. Unless of course, as pointed out, x is also infinity or “nan” (“not a number”). Additionally (Python 2.x ONLY), in a … Read more