You need to create a class that holds the user values, just like the response class User. Add a property to the Response class ‘user’ with the type of the new class for the user values User. public class Response { public string id { get; set; } public string text { get; set; } … Read more
You can do this using Jackson: mapper.readerForUpdating(object).readValue(json); See also Merging Two JSON Documents Using Jackson
This is the solution outlined by Manoj: If you want to suppress serialization of a specific property Foo, but still be able to deserialize it, you can add a method public bool ShouldSerializeFoo() that always returns false. Example: public class Circle2 { public double Diameter { get; set; } public double Radius { get { … Read more
You don’t need to use JsonConverterAttribute, just keep your model clean and use CustomCreationConverter instead, the code is simpler: public class SampleConverter : CustomCreationConverter<ISample> { public override ISample Create(Type objectType) { return new Sample(); } } Then: var sz = JsonConvert.SerializeObject( sampleGroupInstance ); JsonConvert.DeserializeObject<SampleGroup>( sz, new SampleConverter()); Documentation: Deserialize with CustomCreationConverter
When you register a regular type adapter (GsonBuilder.registerTypeAdapter), it only generates a type adapter for THAT specific class. For example: public abstract class Animal { abstract void speak(); } public class Dog extends Animal { private final String speech = “woof”; public void speak() { System.out.println(speech); } } // in some gson related method gsonBuilder.registerTypeAdapter(Animal.class, … Read more
The simplest way is deserialize array of key-value pairs to IDictionary<string, string>: public class SomeData { public string Id { get; set; } public IEnumerable<IDictionary<string, string>> Data { get; set; } } private static void Main(string[] args) { var json = “{ \”id\”: \”123\”, \”data\”: [ { \”key1\”: \”val1\” }, { \”key2\” : \”val2\” } … Read more
In general, there’s no way (in a browser) to serialize objects with functions attached to them: Every function has a reference to its outer scope, that scope won’t exist when you deserialize it, so serialized references to that scope will be invalid. What I would do is use the built-in (or json2.js) JSON.stringify and JSON.parse … Read more
There are multiple ways; before version 1.8, simplest way is probably to do: @JsonDeserialize(as=Cat.class) public abstract class AbstractAnimal { … } as to deciding based on attribute, that is best done using @JsonTypeInfo, which does automatic embeddeding (when writing) and use of type information. There are multiple kinds of type info (class name, logical type … Read more
Ended up creating a converter: public class BoolConverter : JsonConverter { public override void WriteJson(JsonWriter writer, object value, JsonSerializer serializer) { writer.WriteValue(((bool)value) ? 1 : 0); } public override object ReadJson(JsonReader reader, Type objectType, object existingValue, JsonSerializer serializer) { return reader.Value.ToString() == “1”; } public override bool CanConvert(Type objectType) { return objectType == typeof(bool); } … Read more
After searching through Apples Documentation about objc Runtime and according to this SO answer I finally got it working. I just want to share my results. unsigned int count; objc_property_t* props = class_copyPropertyList([MyObject class], &count); for (int i = 0; i < count; i++) { objc_property_t property = props[i]; const char * name = property_getName(property); … Read more