Total no of Binary Trees are = Summing over i gives the total number of binary search trees with n nodes. The base case is t(0) = 1 and t(1) = 1, i.e. there is one empty BST and there is one BST with one node. So, In general you can compute total no of … Read more
To squabble about the performance of binary-trees is meaningless – they are not a data structure, but a family of data structures, all with different performance characteristics. While it is true that unbalanced binary trees perform much worse than self-balancing binary trees for searching, there are many binary trees (such as binary tries) for which … Read more
Summary Type BST (*) Heap Insert average log(n) 1 Insert worst log(n) log(n) or n (***) Find any worst log(n) n Find max worst 1 (**) 1 Create worst n log(n) n Delete worst log(n) log(n) All average times on this table are the same as their worst times except for Insert. *: everywhere in … Read more
Here’s the version with one stack and without a visited flag: private void postorder(Node head) { if (head == null) { return; } LinkedList<Node> stack = new LinkedList<Node>(); stack.push(head); while (!stack.isEmpty()) { Node next = stack.peek(); boolean finishedSubtrees = (next.right == head || next.left == head); boolean isLeaf = (next.left == null && next.right == … Read more
Check out Printing Binary Trees in Ascii From @AnyOneElse Pastbin below: !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! !!!Code originally from /http://www.openasthra.com/c-tidbits/printing-binary-trees-in-ascii/ !!! Just saved it, cause the website is down. !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! Printing Binary Trees in Ascii Here we are not going to discuss what binary trees are (please refer this, if you are looking for binary search trees), or their … Read more
Once expressed in big-O() notation, both are correct. However, during the derivation of the O() polynomial, in the case of binary search, only log2 is correct. I assume this distinction was the intuitive inspiration for your question to begin with. Also, as a matter of my opinion, writing O(log2 N) is better for your example, … Read more
Starting from root node and moving downwards if you find any node that has either p or q as its direct child then it is the LCA. (edit – this should be if p or q is the node’s value, return it. Otherwise it will fail when one of p or q is a direct … Read more
Here is my simple recursive implementation of binary search tree. #!/usr/bin/python class Node: def __init__(self, val): self.l = None self.r = None self.v = val class Tree: def __init__(self): self.root = None def getRoot(self): return self.root def add(self, val): if self.root is None: self.root = Node(val) else: self._add(val, self.root) def _add(self, val, node): if val … Read more
Here’s just an outline of the idea: In a BST, the left subtree of node T contains only elements smaller than the value stored in T. If k is smaller than the number of elements in the left subtree, the kth smallest element must belong to the left subtree. Otherwise, if k is larger, then … Read more
Print a [large] tree by lines. output example: z ├── c │ ├── a │ └── b ├── d ├── e │ └── asdf └── f code: public class TreeNode { final String name; final List<TreeNode> children; public TreeNode(String name, List<TreeNode> children) { this.name = name; this.children = children; } public String toString() { StringBuilder buffer = new StringBuilder(50); print(buffer, “”, “”); return buffer.toString(); } … Read more