The most efficient way of doing this in my opinion is to just increment the string variable. $str=”a”; echo ++$str; // prints ‘b’ $str=”z”; echo ++$str; // prints ‘aa’ As seen incrementing ‘z’ give ‘aa’ if you don’t want this but instead want to reset to get an ‘a’ you can simply check the length … Read more
First effort, with just a-z then aa-zz public static IEnumerable<string> GetExcelColumns() { for (char c=”a”; c <= ‘z’; c++) { yield return c.ToString(); } char[] chars = new char[2]; for (char high=”a”; high <= ‘z’; high++) { chars[0] = high; for (char low = ‘a’; low <= ‘z’; low++) { chars[1] = low; yield return … Read more
(Assumes ASCII, etc) for (char c=”A”; c <= ‘Z’; c++) { //do something with letter } Alternatively, you could split it out to a provider and use an iterator (if you’re planning on supporting internationalisation): public class EnglishAlphabetProvider : IAlphabetProvider { public IEnumerable<char> GetAlphabet() { for (char c=”A”; c <= ‘Z’; c++) { yield return … Read more
I don’t think there is a built in way, but I think the easiest would be char[] alpha = “ABCDEFGHIJKLMNOPQRSTUVWXYZ”.ToCharArray();
Assuming you want lower case letters: var chr = String.fromCharCode(97 + n); // where n is 0, 1, 2 … 97 is the ASCII code for lower case ‘a’. If you want uppercase letters, replace 97 with 65 (uppercase ‘A’). Note that if n > 25, you will get out of the range of letters.
>>> import string >>> string.ascii_lowercase ‘abcdefghijklmnopqrstuvwxyz’ If you really need a list: >>> list(string.ascii_lowercase) [‘a’, ‘b’, ‘c’, ‘d’, ‘e’, ‘f’, ‘g’, ‘h’, ‘i’, ‘j’, ‘k’, ‘l’, ‘m’, ‘n’, ‘o’, ‘p’, ‘q’, ‘r’, ‘s’, ‘t’, ‘u’, ‘v’, ‘w’, ‘x’, ‘y’, ‘z’] And to do it with range >>> list(map(chr, range(97, 123))) #or list(map(chr, range(ord(‘a’), ord(‘z’)+1))) [‘a’, … Read more