org.glassfish.jersey.servlet.ServletContainer ClassNotFoundException

The problem:

java.lang.ClassNotFoundException: org.glassfish.jersey.servlet.ServletContainer

indicates that you try to use the Jersey 2.x servlet, but you are supplying the Jersey 1.x libs.

For Jersey 1.x you have to do it like this:

<servlet>
  <servlet-name>Jersey REST Service</servlet-name>
<servlet-class>
  com.sun.jersey.spi.container.servlet.ServletContainer
</servlet-class>
  <init-param>
    <param-name>com.sun.jersey.config.property.packages</param-name>
    <param-value>sample.hello.resources</param-value>
  </init-param>
  <load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
  <servlet-name>Jersey REST Service</servlet-name>
  <url-pattern>/rest/*</url-pattern>
</servlet-mapping>

For more information check the Jersey 1.x documentation.

If you instead want to use Jersey 2.x then you’ll have to supply the Jersey 2.x libs. In a maven based project you can use the following:

<dependency>
    <groupId>org.glassfish.jersey.containers</groupId>
    <artifactId>jersey-container-servlet</artifactId>
    <version>2.xx</version>
</dependency>
<!-- if you are using Jersey client specific features without the server side -->
<dependency>
    <groupId>org.glassfish.jersey.core</groupId>
    <artifactId>jersey-client</artifactId>
    <version>2.xx</version>
</dependency>

For Jersey 2.x you don’t need to setup anything in your web.xml, it is sufficient to supply a class similar to this:

import javax.ws.rs.ApplicationPath;
import javax.ws.rs.core.Application;

@ApplicationPath("rest")
public class ApplicationConfig extends Application {

}

For more information, check the Jersey documentation.

See also:

  • java.lang.ClassNotFoundException: com.sun.jersey.spi.container.servlet.ServletContainer
  • Jersey Services with Tomcat and Eclipse
  • ClassNotFoundException when starting tomcat

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