Java – Order of Operations – Using Two Assignment Operators in a Single Line

= is parsed as right-associative, but order of evaluation is left-to-right.

So: The statement is parsed as a[i] = (i = 9). However, the expression i in a[i] is evaluated before the right hand side (i = 9), when i is still 0.

It’s the equivalent of something like:

int[] #0 = a;
int #1 = i;
int #2 = 9;
i = #2;
#0[#1] = #2;

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