The reason is, that “” is not a valid double. You need to test the String before or catch such exceptions
double w;
try {
w = new Double(input3.getText().toString());
} catch (NumberFormatException e) {
w = 0; // your default value
}
The reason is, that “” is not a valid double. You need to test the String before or catch such exceptions
double w;
try {
w = new Double(input3.getText().toString());
} catch (NumberFormatException e) {
w = 0; // your default value
}