How to catch an exception in Java? [closed]

try {
   int userValue = Integer.parseInt(aString);
} catch (NumberFormatException e) {
   //there you go
}

and specifically in your code:

public void actionPerformed(ActionEvent e) {
    String str;
    int no;
    //------------------------------------
    try {
       //lots of ifs here
    } catch (NumberFormatException e) {
        //do something with the exception you caught
    }

    if (e.getSource() == finish) {
        if (message.getText().equals("")) {
            JOptionPane.showMessageDialog(null, "Please Enter the Input First");
        } else {
            leftButtons();

        }
    }
    //rest of your code
}

Leave a Comment