When using async
and await
the compiler generates a state machine in the background.
Here’s an example on which I hope I can explain some of the high-level details that are going on:
public async Task MyMethodAsync()
{
Task<int> longRunningTask = LongRunningOperationAsync();
// independent work which doesn't need the result of LongRunningOperationAsync can be done here
//and now we call await on the task
int result = await longRunningTask;
//use the result
Console.WriteLine(result);
}
public async Task<int> LongRunningOperationAsync() // assume we return an int from this long running operation
{
await Task.Delay(1000); // 1 second delay
return 1;
}
OK, so what happens here:
-
Task<int> longRunningTask = LongRunningOperationAsync();
starts executingLongRunningOperation
-
Independent work is done on let’s assume the Main Thread (Thread ID = 1) then
await longRunningTask
is reached.Now, if the
longRunningTask
hasn’t finished and it is still running,MyMethodAsync()
will return to its calling method, thus the main thread doesn’t get blocked. When thelongRunningTask
is done then a thread from the ThreadPool (can be any thread) will return toMyMethodAsync()
in its previous context and continue execution (in this case printing the result to the console).
A second case would be that the longRunningTask
has already finished its execution and the result is available. When reaching the await longRunningTask
we already have the result so the code will continue executing on the very same thread. (in this case printing result to console). Of course this is not the case for the above example, where there’s a Task.Delay(1000)
involved.