Edit: the recommended way is now to use JavaConverters
and the .asScala
method:
import scala.collection.JavaConverters._
val myScalaMap = myJavaMap.asScala.mapValues(_.asScala.toSet)
This has the advantage of not using magical implicit conversions but explicit calls to .asScala
, while staying clean and consise.
The original answer with JavaConversions
:
You can use scala.collection.JavaConversions
to implicitly convert between Java and Scala:
import scala.collection.JavaConversions._
val myScalaMap = myJavaMap.mapValues(_.toSet)
Calling mapValues
will trigger an implicit conversion from the java Map
to a scala Map
, and then calling toSet
on the java collection with implicitly convert it to a scala collection and then to a Set
.
By default, it returns a mutable Map
, you can get an immutable one with an additional .toMap
.
Short-ish example:
scala> val a: java.util.Map[String, java.util.Collection[String]] = new java.util.HashMap[String, java.util.Collection[String]]
a: java.util.Map[String,java.util.Collection[String]] = {}
scala> val b = new java.util.ArrayList[String]
b: java.util.ArrayList[String] = []
scala> b.add("hi")
res5: Boolean = true
scala> a.put("a", b)
res6: java.util.Collection[String] = []
scala> import scala.collection.JavaConversions._
import scala.collection.JavaConversions._
scala> val c = a.mapValues(_.toSet)
c: scala.collection.Map[String,scala.collection.immutable.Set[String]] = Map(a -> Set(hi))
scala> c.toMap
res7: scala.collection.immutable.Map[String,scala.collection.immutable.Set[String]] = Map(a -> Set(hi))