That’s by design.
If you have component with OnPush
change detection then its detectChangesInternal
function won’t be triggered unless one of four things happens:
1) one of its @Inputs
changes
~2.4.x
~4.x.x
Note: @Input
s should be presented in template. See issue https://github.com/angular/angular/issues/20611 and comment
2) a bound event is triggered from the component (that is your case)
Caveats: There is some difference here between 2.x.x and 4
Angular ChangeDetectionStrategy.OnPush with child component emitting an event
~2.4.x
~4.x.x
3) you manually mark the component to be checked (ChangeDetectorRef.markForCheck()
)
4) async pipe calls ChangeDetectorRef.markForCheck()
internally
private _updateLatestValue(async: any, value: Object): void {
if (async === this._obj) {
this._latestValue = value;
this._ref.markForCheck();
}
}
https://github.com/angular/angular/blob/2.4.8/modules/%40angular/common/src/pipes/async_pipe.ts#L137
In other words if you set OnPush
for component then after the first checking component’s status will be changed from CheckOnce
to Checked
and after that it’s waiting as long as we do not change status. It will happen in one of three things above.
See also:
- https://github.com/angular/angular/issues/11678#issuecomment-247894782
There are also good explanations of how angular2 change detection work:
- https://blog.thoughtram.io/angular/2016/02/22/angular-2-change-detection-explained.html
- https://hackernoon.com/everything-you-need-to-know-about-change-detection-in-angular-8006c51d206f
Here is Live Example(Thanks to Paskal) that explains onPush
change detection. (Comp16
looks like your component. You can click at this box).