You could stream the array, and filter using String::contains. String[] words = {“bad”, “bat”,”hat”}; String filter = “at”; List<String> list = Stream.of(words) .filter(word -> word.contains(filter)) .collect(Collectors.toList()); System.out.println(list);
Here’s a text (comment) illustrated explanation (both the question and the answer): public Object[] methodA() { // We are method A // In which we create an array Object[] someArrayCreatedInMethodA = new Object[10]; // And we can returned someArrayCreatedInMethodA return someArrayCreatedInMethodA; } public void methodB() { // Here we are inside another method B // … Read more
The second one, because the first one uses the raw type instead of generics. i.e. List is raw, but List<?> is generic, and you shouldn’t mix-and-match between both raws and generics.
if you use SOAP do sth like this : String namespace = “http://tempuri.org/” ; String soapAction = “http://tempuri.org/MyMethod”; String methodName = “MyMethod”; String url = “http://192.168.1.2:8686/WebService/MyWebService.asmx” ; // my local or valid ip for webservice location SoapObject request = new SoapObject(namespace, methodName); // your webservice argument String username = “your username”; PropertyInfo usernameProp = new … Read more
setValue() and SetValue() are two different things. Names are case sensitive. That’s why compiler couldn’t find setValue() since you typed SetValue()!
Here are some hints you may need: 1) If you use / on arguments which will be integers then your result will also be integer. Example: int x = 7/2; System.out.println(x); output: 3 (not 3.5) So to get rid of last digit of integer all you can do is divide this number by 10 like … Read more
Java is always pass-by-value. Unfortunately, when we deal with objects we are really dealing with object-handles called references which are passed-by-value as well. This terminology and semantics easily confuse many beginners. It goes like this: public static void main(String[] args) { Dog aDog = new Dog(“Max”); Dog oldDog = aDog; // we pass the object … Read more
== tests for reference equality (whether they are the same object). .equals() tests for value equality (whether they are logically “equal”). Objects.equals() checks for null before calling .equals() so you don’t have to (available as of JDK7, also available in Guava). Consequently, if you want to test whether two strings have the same value you … Read more
When you declare a reference variable (i.e., an object), you are really creating a pointer to an object. Consider the following code where you declare a variable of primitive type int: int x; x = 10; In this example, the variable x is an int and Java will initialize it to 0 for you. When … Read more