For the short answer, you need to do three things: Remove the new { Checked = “checked” } from the second radio button. This hard-coded checked value will override all of the magic. When you return your ViewResult from the controller action, give it an instance of your model class where TermsAndConditions is false. This … Read more
You need to put the entire ternary expression in parenthesis. Unfortunately that means you can’t use “@:”, but you could do something like this: @(deletedView ? “Deleted” : “Created by”) Razor currently supports a subset of C# expressions without using @() and unfortunately, ternary operators are not part of that set.
Since System.ComponentModel.DataAnnotations.FileExtensionsAttribute is sealed. I use a wrapper for MVC 4. public class HttpPostedFileExtensionsAttribute : DataTypeAttribute, IClientValidatable { private readonly FileExtensionsAttribute _innerAttribute = new FileExtensionsAttribute(); /// <summary> /// Initializes a new instance of the <see cref=”HttpPostedFileExtensionsAttribute” /> class. /// </summary> public HttpPostedFileExtensionsAttribute() : base(DataType.Upload) { ErrorMessage = _innerAttribute.ErrorMessage; } /// <summary> /// Gets or sets … Read more
When should I use View Models? Is it not recommended to use the domain? I find that my view models are copies of my domain objects, and don’t see the value… View models should always be used. You should not use your domain models in the view. View models are not exact copies of the … Read more
The reason why this doesn’t work is because of a limitation of the DropDownListFor helper: it is able to infer the selected value using the lambda expression passed as first argument only if this lambda expression is a simple property access expression. For example this doesn’t work with array indexer access expressions which is your … Read more
As far as receiving a JSON string and binding it to a model is concerned the JsonValueProviderFactory does this job out of the box in ASP.NET MVC 3. But there is nothing built-in for outputting JSONP. You could write a custom JsonpResult: public class JsonpResult : JsonResult { public override void ExecuteResult(ControllerContext context) { if … Read more
Sounds like you’re missing the following in the Web.Config in the views folder: /Views/Web.Config <?xml version=”1.0″?> <configuration> <system.web.webPages.razor> <host factoryType=”System.Web.Mvc.MvcWebRazorHostFactory, System.Web.Mvc, Version=3.0.0.0, Culture=neutral, PublicKeyToken=31BF3856AD364E35″ /> <pages pageBaseType=”System.Web.Mvc.WebViewPage”> // <– this line and contents are important <namespaces> <add namespace=”System.Web.Mvc” /> <add namespace=”System.Web.Mvc.Ajax” /> <add namespace=”System.Web.Mvc.Html” /> <add namespace=”System.Web.Routing” /> </namespaces> </pages> </system.web.webPages.razor> Views typically derive from … Read more
Try something like this: <script type=”text/javascript”> $(function () { $(‘#dialog’).dialog({ autoOpen: false, width: 400, resizable: false, title: ‘hi there’, modal: true, open: function(event, ui) { //Load the CreateAlbumPartial action which will return // the partial view _CreateAlbumPartial $(this).load(“@Url.Action(“CreateAlbumPartial”)”); }, buttons: { “Close”: function () { $(this).dialog(“close”); } } }); $(‘#my-button’).click(function () { $(‘#dialog’).dialog(‘open’); }); }); … Read more
All you need is: @Html.Raw(yourEncodedHtmlFromYouDatabase) I’m assuming that the html in the database has been properly sanitized (or at least from a reliable source), because if not, you could be opening yourself up to cross-site scripting attacks. The reason your approach didn’t work is that Razor HTML-encodes output by default (every time you use @ … Read more
Update: If you are using a newer version of MVC, the same process applies, just be sure to use the correct version number in the web.config’s <host> line. Well, I found myself experiencing the same thing you did, and after a bit further research, I found out what the problem is! You need to include … Read more