Since Python 3.6 there is a method choices
from the random
module.
In [1]: import random
In [2]: random.choices(
...: population=[['a','b'], ['b','a'], ['c','b']],
...: weights=[0.2, 0.2, 0.6],
...: k=10
...: )
Out[2]:
[['c', 'b'],
['c', 'b'],
['b', 'a'],
['c', 'b'],
['c', 'b'],
['b', 'a'],
['c', 'b'],
['b', 'a'],
['c', 'b'],
['c', 'b']]
Note that random.choices
will sample with replacement, per the docs:
Return a
k
sized list of elements chosen from the population with replacement.
Note for completeness of answer:
When a sampling unit is drawn from a finite population and is returned
to that population, after its characteristic(s) have been recorded,
before the next unit is drawn, the sampling is said to be “with
replacement”. It basically means each element may be chosen more than
once.
If you need to sample without replacement, then as @ronan-paixão’s brilliant answer states, you can use numpy.choice
, whose replace
argument controls such behaviour.